From 3b6f0d4c7d3bd2a53469c5b0484908f42d9c066f Mon Sep 17 00:00:00 2001
From: Egor Tensin <Egor.Tensin@gmail.com>
Date: Sun, 18 Feb 2018 04:46:38 +0300
Subject: peculiar: move to _posts/

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----
-title: Peculiar Haskell indentation
-layout: post
-excerpt: >
-  An explanation of how Haskell indentation works inside <code>do</code>
-  blocks.
-category: Haskell
-custom_css:
-  - syntax.css
----
-I've fallen into a Haskell indentation pitfall.
-I think it must be common, so I'm describing it here.
-
-The problem is that indentation rules in `do` blocks are not intuitive to me.
-For example, the following function is valid Haskell syntax:
-
-```haskell
-foo1 :: IO ()
-foo1 =
-    alloca $ \a ->
-    alloca $ \b ->
-    alloca $ \c -> do
-        poke a (1 :: Int)
-        poke b (1 :: Int)
-        poke c (1 :: Int)
-        return ()
-```
-
-In fact, this funnier version is also OK:
-
-```haskell
-foo2 :: IO ()
-foo2 = alloca $ \a ->
-     alloca $ \b ->
-   alloca $ \c -> do
-       poke a (1 :: Int)
-       poke b (1 :: Int)
-       poke c (1 :: Int)
-       return ()
-```
-
-If you add an outer `do` however, things become a little more complicated.
-For example, this is the valid version of the functions above with an outer
-`do`:
-
-```haskell
-foo3 :: IO ()
-foo3 = do
-    alloca $ \a ->
-        alloca $ \b ->
-            alloca $ \c -> do
-                poke a (1 :: Int)
-                poke b (1 :: Int)
-                poke c (1 :: Int)
-                return ()
-```
-
-Notice the extra indentation for each of the `alloca`s.
-When I tried to remove these seemingly excessive indents, GHC complained with
-the usual `parse error (possibly incorrect indentation or mismatched
-brackets)`.
-
-```haskell
-foo4 :: IO ()
-foo4 = do
-    alloca $ \a ->
-    alloca $ \b ->
-    alloca $ \c -> do
-        poke a (1 :: Int)
-        poke b (1 :: Int)
-        poke c (1 :: Int)
-        return ()
-```
-
-The truth is, the rules for desugaring `do` blocks are surprisingly simple and
-literal.
-GHC inserts semicolons according to the rules [found in the Wikibook].
-So it inserts semicolons between the `alloca`s on the same level, so `foo4`
-becomes:
-
-```haskell
-foo4 :: IO ()
-foo4 = do
-    { alloca $ \a ->
-    ; alloca $ \b ->
-    ; alloca $ \c -> do
-        { poke a (1 :: Int)
-        ; poke b (1 :: Int)
-        ; poke c (1 :: Int)
-        ; return ()
-        }
-    }
-```
-
-[found in the Wikibook]: https://en.wikibooks.org/wiki/Haskell/Indentation#Explicit_characters_in_place_of_indentation
-
-The semicolons after `->` are clearly invalid Haskell syntax, hence the error.
-
-P.S. To compile the functions above, you need to include them in a module and
-add proper imports, e.g.
-
-```haskell
-module PeculiarIndentation where
-
-import Foreign.Marshal.Alloc (alloca)
-import Foreign.Storable      (poke)
-```
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